Question 8 (I credit) In fact, we can do better than the divide-and-conquer approach for the maximum subarray problem. User the following ideas to develop a non-recursive, linear-time algorithm for the maximum- subarray problem. Start at the left end of the array, and progress toward the right, keeping track of the maximum subarray seen so far. Knowing a maximum subarray of A[1. j], extend the answer to find a maximum subarray ending at index j + 1 using the following observation: a maximum subarray of A[i..j + 1] is either a maximum subarray of A[1..j] or a subarray A[i..j + 1], for some 1 s i j 1. Finding a maximum subarray of A[i..j + 1] can be done in constant time, because we already know the maximum subarray of A[1..j]. Please write down the pseudocode