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Question Above: IEEE 754-2008 contains a half precision that is only 16 bits wide.The leftmost bit is still the sign bit, the exponent is 5

Question Above: IEEE 754-2008 contains a half precision that is only 16 bits wide.The leftmost bit is still the sign bit, the exponent is 5 bits wide and has a bias of 15, and the mantissa is 10 bits long. A hidden 1 is assumed. Write down the bit pattern to represent -1.6875 X 100 assuming a version of this format, which uses an excess-16 format to store the exponent. Comment on how the range and accuracy of this 16-bit floating point format compares to the single precision IEEE 754 standard.

Question to be answered: Calculate the sum of 2.6125 x 101 and 4.150390625 x 10-1, assuming A and B are stored in the 16-bit half precision described in Question above. Assume 1 guard, 1 round bit and 1 sticky bit and round to the nearest even. Show all the steps.

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