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Part 1

In a survey of 2909 adults, 1400 say they have started paying bills online in the last year.

Construct a99% confidence interval for the population proportion. Interpret the results.

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Part 1

A99% confidence interval for the population proportion is

enter your response here,enter your response here.

(Round to three decimal places asneeded.)

Use the given confidence interval to find the margin of error and the sample proportion.

(0.654,0.682)

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Part 2

E=enter your response here

(Type an integer or adecimal.)

In a survey of 2379 adults in a recentyear, 1320 say they have made a NewYear's resolution.

Construct90% and95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals.

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Part 3

The90% confidence interval for the population proportion p is

enter your response here,enter your response here.

(Round to three decimal places asneeded.)

In a survey of 3294 adults, 1402 say they have started paying bills online in the last year.

Construct a99% confidence interval for the population proportion. Interpret the results.

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Part 4

A99% confidence interval for the population proportion is

enter your response here,enter your response here.

(Round to three decimal places asneeded.)