Question Description The lamp is protected by depositing indium-tin-oxide (BaTiOs) as a cover on all parts except beryllium window. The mass absorption coefficient of barium, titanium, and oxygen for Cu-Kai radiatio are 333.4, 221.7, and 16.3 cm/g, respectively. Atomic masses: M(Ba)%3D137.3 g/mol, M(Ti)-47.9 g/mol, and M(O)=16.0g/mol. Density of barium titanate (BaTiO3) is 6.02 g/cm'. Calculate mass absorption coefficient of BaTiO; and determine what minimum thickness of BaTiO, could be used to fabricate the protective shield if at least 99.5% of the Cu-Kat radiation is to be absorbed by it?