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question is below: point (1, 0, 2, -1). Let f(w, x, y, z) = (2w + xz, yx2 + 2w - z, wax + 3y).
question is below:
point (1, 0, 2, -1). Let f(w, x, y, z) = (2w + xz, yx2 + 2w - z, wax + 3y). Compute the Jacobian matrix [Jf(w, x, y, z)] at an arbitrary point (w, x, y, z) and at the 2 Z 0 X [Jf(w, x, y, z) ] = 2 2y^2x 2x^2y -1 2xw W/2 3 0 2 -1 0 0 [Jf(1, 0, 2, -1)] = 2 0 0 -1 0 3 0 2 Now consider f (1, 0, 2, -1) = 3 6 . If we change the input point (1, 0, 2, -1) by h = (-0.1, -0.1, 0.1, 0.1), then the approximate change 0 in the function (as estimated by the derivative) is 0 2 , and the approximate value of the function is f (0.9, -0.1, 2.1, -0.9) ~ 0 2 6Step by Step Solution
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