Question is in the attachment.

Problem 2 (8 pts) A customer is trying to reach his phone company to suspend the caller i.d. service of his line. He calls 1-800-PHONEME once and again until the line is not busy and an operator answers the call. Let X be the random variable that counts the number of times the customer gets a busy line before reaching an operator, then fx(x) = q'p ifx = 0, 1,2, . . . 0 otherwise where p is the probability of getting an operator and q =1 - p. (1) What is the probability that he will get a busy line exactly two times? (1 pt) (2) What is the probability that the customer will get a busy line 5 or more times? Your answer should be a very simple function of q. (3 pts)