Question Try putting a SuperInt on the right hand side of an assignment statement using theValue() Does it work Why Take away nothing too interesting, we can return the value of an instance variable But, in this case we are returning the reference to the variable Try putting a SuperInt on the left hand side of an assignment statement using theValue() Does it work Why Take away First, returning a const type means the function cannot be a l value Second, if the the return type is not of const , then, if the receiver of this function is an integer reference, then, the receiver can change this instance variable Ask me if you don't understand what I mean Coding (finish in 20min) Update the member function theValue() of SuperInt class so that SuperInt can be put on the left hand side of an assignment statement using theValue() Create a new class SuperSuperInt, which inherits the SuperInt class Please declare and define this class in separate h and cpp files, and DO NOT update SuperInt h and SuperInt cpp directly Please name your new files as SuperSuperInt cpp and SuperSuperInt h Add one member function theValue() to SuperSuperInt Code the member function theValue() of SuperSuperInt to return the value of data member myValue in SuperInt Please make sure the returned value of theValue() CANNOT be put on the left hand side of an assignment statement include class Super Int public Name helps us see which variable SuperInt(int init, const char name) Super Int() For demonstrating lvalues int theValue(void) const int theValue(void) private int myValue std string myName Neat trick making this private prevents creating unitialized objects SuperInt() include class Super Int public Name helps us see which variable SuperInt(int init, const char name) Super Int() For demonstrating lvalues int theValue(void) const int theValue(void) private int myValue std string myName Neat trick making this private prevents creating unitialized objects SuperInt()

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Question Try putting a SuperInt on the right hand side of an assignment statement using theValue(). Does it work? Why? Take away: nothing too interesting,

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Try putting a SuperInt on the right hand side of an assignment statement using theValue(). Does it work? Why?
- Take away: nothing too interesting, we can return the value of an instance variable. But, in this case we are returning the reference to the variable!
Try putting a SuperInt on the left hand side of an assignment statement using theValue(). Does it work? Why?
- Take away: First, returning a const type means the function cannot be a l-value. Second, if the the return type is not of const , then, if the receiver of this function is an integer reference, then, the receiver can change this instance variable! Ask me if you don't understand what I mean.

Coding (finish in 20min)

Update the member function theValue() of SuperInt class so that SuperInt can be put on the left hand side of an assignment statement using theValue().
Create a new class "SuperSuperInt," which inherits the "SuperInt" class. Please declare and define this class in separate .h and .cpp files, and DO NOT update SuperInt.h and SuperInt.cpp directly. Please name your new files as "SuperSuperInt.cpp" and "SuperSuperInt.h."
Add one member function theValue() to SuperSuperInt.
Code the member function theValue() of SuperSuperInt to return the value of data member "myValue" in SuperInt. Please make sure the returned value of theValue() CANNOT be put on the left hand side of an assignment statement.

#include class Super Int { public: // Name helps us see which variable SuperInt(int init, const char *name); - Super Int(); // For demonstrating lvalues //int& theValue(void); const int& theValue(void); private: int myValue; std::string myName; // Neat trick: making this private prevents creating unitialized // objects SuperInt(); #include class Super Int { public: // Name helps us see which variable SuperInt(int init, const char *name); - Super Int(); // For demonstrating lvalues //int& theValue(void); const int& theValue(void); private: int myValue; std::string myName; // Neat trick: making this private prevents creating unitialized // objects SuperInt()