Questions 1. If the KHP you were given in part A was contaminated with KCl, would the calculated molarity of NaOH be too high, too low, or unaffected. Explain. 2. Describe the advantage of performing more trials of the titration versus doing only a single trial. 3. A 0.750 g impure sample of KHP is 38.3% KHP. How many milliliters of 0.117 M NaOH would be required to completely neutralize the KHP? Part B Determination of the percent mass of an unknown KHP sample 451 Unknown Number of KHP sample Mass of impure KHP Initial Volume of NaOH -769 5 aC 125 ml 12.0mL ..slos - 63.74% Final Volume of NaOH Volume of NaOH Dispensed Mass of KHP in sample % KHP in sample Calculations 37.1 2299 +1600t 1,008. 39.10+ 1.008 309 .20 N.oh & Nott & state nellt (12812,5) = 2. Sure NaOH = 2.5 mx 284.22 = 12.00-167.7126) -1.510g % 510 & lou 761