Questions 10-18 are related to the following information A population has a mean of 1505.77 and standard deviation of 259.35 10 A random sample of size n= 80 s selected from this population. The probability that the sample mean exceed 1523 is, 0.2762 0.2938 0.3126 0.3325 11 The fraction of the means from samples of size n: 80 that are below 1480 is. 0. 1618 0.1740 0. 1871 0.2012 12 What fraction of the means from random samples of siz 80 are : 40 from the population mean 0.8572 0.8323 0.8060 0.7845 73 The margin of error for the middle interval that captures 95% of the sample means from samples of size 80 is. 58.59 56.8 55.13 53.47 14 The middle interval that captures 95% of the means from samples of size 80 is. 1458.57 1552.97 1455.55 1555.99 1452.35 1559. 19 1448.94 1562.60 15 Suppose we double the sample size ton = 2 * 80 = 160. Regarding the impact of changing the sample size on the margin of sampling error, doubling the sample size, but keeping the error probability a at 5%, would, Increase by 50% Decrease b 50% Decrease b 29% Jecrease b 38%% 16 If we kept n at 80 but reduced the error probability to a = 0.01, the margin of error would ... Decrease b 20% Increase by 20% Increase by 24% Increase by 31% 17 The middle interval that captures 93% of all means from samples of size 80 1435.5 1576.0 1433.3 1578.2 1431.1 1580.5 1428.8 1582.8 Now keep the error probability at a = 0.05. We want to build an interval which captures 95% of the sample means within $15 from the population mean. What is the minimum sample size that would yield such an 838 931 1034 1149