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Questions 6-15: Compare arm span x (cm) and height y (cm) of 6 individuals. Assume normality of the data. Let /r be the true mean

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Questions 6-15: Compare arm span x (cm) and height y (cm) of 6 individuals. Assume normality of the data. Let /r be the true mean of arm span and let My be the true mean of height. X 180 172 181 163 160 198 176 175 177 164 155 186 6. Test to see if the mean arm span is significantly different from height. What are the proper hypotheses? O Ho: He = Hy vs HA: HI # Hy O Ho: He Hy O Ho: He = Hy vs HA: HI > Hy O Ho: He = Hy vs HA: HI - My O Ho: He > Hy vs HA: HI My 7. Using a 0.05 level of significance, what is your conclusion? O Reject HA O Do not reject Ho O Accept Ho O Reject Ho O Fail to reject HA 8. Construct a 90% confidence interval for HI - My. O (-0.825, 7.825) O (-3.693, 10.693); O (-1.338, 8.338); O (-3.287, 10.287); O (-2.537, 9.537); Now consider a linear regression model (using the same arm span and height data), y = Bot Biate with e~ N(0, a?) 9. What is the estimated expected change in height for 1 cm increase in arm span? O 0.94 O 0.74 O 0.93 O 0.51 O 0.8710. What is the estimated error variance o'? O 17.37 O 11.6 0 5.16 O 18.8 O 17.93 11. What is coefficient of determination R?? O 0.54 O 0.62 O 0.57 O 0.88 O 0.6 12. What is sample correlation coefficient r? O 0.16 O -0.08 O 0.15 O 0.25 O 0.94 13. Test Ho: B1 = 1vs HA: P1 / 1. what is the test statistic? O -1.18 O -1.91 1.91 O 0.63 O -1.26 14. Find 95% confidence interval for mean response E(y) at x= 190. O (178.01, 187.51); O (176.71, 188.81); O (175.51, 190.01) O (171.01, 194.51); O (178.71, 186.81);15. Find 95% prediction interval of y at x= 190. O (178.23, 187.28); O (163.23, 202.28); O (168.93, 196.58) O (157.83, 207.68); O (170.13, 195.38)

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