Questions (a) - (d) are based on the ALU design shown below 2 8B out [N-1] IS 1:0 2 (a) Consider that F2 (the MSB of F2o) is stuck-at-one. This means that due to some hardware defect F2 does not change to O if we try to change it to 0- it always has the value 1. Under this defect which one of the following operations will malfunction? 1. Minus (-) 2. SLT 3. OR 4. None of the above Write your choice for above here (as a number between 1-4) (b) Consider that Fo (the LSB of F2o) is stuck-at-zero. Under this defect which one of the following operations will malfunction? 1. Plus (+) 2. SLT 3. AND 4. None of the above Write your choice for above here (as a number between 1-4) (c) The A LU performs subtraction wh 1. The 4:1 MUX chooses the two numbers A and B and passes them to the subtractor 2. The 2:1 MUX chooses the two numbers A and B and passes them to the adder which performs two's complement arithmetic 3. The 2:1 MUX chooses the inverse of B and passes it to the adder; the adder which also receives A as another input, performs two's complement arithmetic by adding A, the inverse of B and the number one (from the F2 signal) 4. None of the above Write your choice for above here (as a number between 1-4) (d) If we want to switch the values of the control signal (that is, Fo2) between the two ALU functions A &-B and A l-B, then the circuit must be changed in the following way 1. Swap the OR and AND gates between their current locations in the circuit 2. Put inverters in front of the outputs from both the OR and AND gates 3. Swap the OR and AND gates between their current locations in the circuit and agree that the control signals of functions A & B and A | B will also get switched 4. None of the above Write your choice for above here (as a number between 1-4)