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Quiz Me: Quiz Me: 12.3-4 Solve applications involving permutations and probability. Question 4 of 4 This quiz: 4 point(s) possible This question: 1 point(s)
Quiz Me: Quiz Me: 12.3-4 Solve applications involving permutations and probability. Question 4 of 4 This quiz: 4 point(s) possible This question: 1 point(s) possible Resume later Submit quiz Assume birthdays are equally likely to occur on any day of the year, and ignore February 29th. Consider only the month and the day, not the year. Complete parts (a) through (d) below. 365 The probability that all three have a different birthdate is 0.9918 (Round to four decimal places as needed.) The probability that at least one birthdate is shared is 0.0082 (Round to four decimal places as needed.) b) Repeat part (a) for a group of 12 randomly chosen people The probability that all 12 have a different birthdate is 0.8330 (Round to four decimal places as needed) The probability that at least one birthdate is shared is 0.1670 (Round to four decimal places as needed.) c) What is the smallest number of randomly-chosen people needed so that the probability of at least one shared birthdate is above 0.75? The smallest number of people required is d) What is the smallest number of randomly chosen people needed for the probability of a shared birthdate to be certain? Select the correct choice below and, if necessary, fill in the answer box within your choice. OA. The smallest number of people required is OB. It would take infinitely many people. (0,0) More Sul
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