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R1 Solve for the equivalent circuit resistance and the currents through R2 and R3 (Ans: 0.946mA. IR3 = 0.473mA) Req = 6.34k. IR2 w
R1 Solve for the equivalent circuit resistance and the currents through R2 and R3 (Ans: 0.946mA. IR3 = 0.473mA) Req = 6.34k. IR2 w 2k 9v 24 R2 4k R4 1.67k R3 8k
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94 for Req I R 2KR R 4k Rq 1672 A Req 94 R R2 R...
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Applied Physics
Authors: Dale ewen, Neill schurter, P. erik gundersen
10th Edition
978-0136116332, 136116337, 9780132830096, 978-0132109277
