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Radium 228 decays by giving off one particle, and the decay can be represented by the nuclear equation 228 88 Ra = __ + 228

Radium 228 decays by giving off one particle, and the decay can be represented by the nuclear equation 228 88 Ra = __ + 228 89 Ac.

1. What is the complete equation?

2. What type of radiation is given off in this reaction?

3. Where does the particle come from, and what is the process of this type of decay?

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