Ray tracing When you have two optical components daisy-chained together, the image of the first one becomes the object for the second.1 The normal rules for ray diagrams (and the Us + \"5': lffequation called the thins lens equation) apply but you need to keep careful track of distances and positions relative to the optical components. In this problem you will work through the following optics scenario where the image from a mirror is fed into a lens: A 20-cm-radius concave mirror is placed atx = 0. A converging lens 0": 5 cm} is placed at x = 50 cm). A 4-cm-tall object is placed at x = 15 cm. Where is the image formed and what is its height? lA. Use ray tracing to (approximately) locate the image produced by the mirror. 15cm 5 m I 13 What are the object distance (5} and focal length (1') for the original object in relation to the mirror? 1C. Use the thin lens formula to calculate the image distance (5") for the image formed by the mirror. 1D. Where (at what position x} is the image formed\"? What is the height of the image? Is it inverted or upright? The image formed by the mirror becomes the object for the lens. 2A. Redraw just the image from part 1 on this diagram with the correct location, height and orientation. Then use ray tracing to (approximately) locate the lens's image. 15 cm 5019m 2B. What is the object distance (s) in relation to the lens? 2C. Use the lens formula to calculate the image distance (s' ) for the image formed by the lens. 2D. Where (at what position x) is the image formed? What is the height of the image? Is it inverted or upright