Re discount on 5 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 5 weekday period jumps to 81. [You may find it useful to reference the z table.] a. What is the probability to get a sample average of 81 or more customers if the manager had not offered the discount? (Round final answer to 4 decimal places.) Answer is complete but not entirely correct. Probability 1.9300