Read the assembly code below; add comments to explain what each of line of code is doing; provide a simple equation to express the return value v0 as a function of input arguments a0 and a1. (35 points)

new-proc: blt $a1, $zero, loop2 loop1: beq $a1, $zero, proc-end sll $a0, $a0, 1 addi $a1, $a1, -1 j loop1 loop2: beq $a1, $zero, proc-end srl $a0, $a0, 1 addi $a1, $a1, 1 j loop2 proc-end: add $v0, $a0, $zero jr $ra