Read the following code carefully and fill in the blanks those follow. VAR num startval := 0; VR num endval := 25; VA num stepvalue := 1; VARm multval := 2; VAR num testval1 := 0; VAR num testval 2:= 200; FOR counterx FROM startval TO endval STEP stepvalue DO testval1 := testval1 + counterx * multval; PICK; DROP: IF testval1 > testval2 EXIT; ENDFOR a) The value of 'counterx' after fourth pick and drop operation will be A/ b) The maximum value of the variable 'testval1' can be A/ This loop will repeat for A times. d) The 'PICK' subroutine will execute for A times. e) The value of the variable 'testval1' will be A at the end of iteration when 'counterx' = 5. f) A Pick & Drop cycles possible in total using the above loop if the step value were initialized to 2. g) The Drop subroutine will be executed for A times if the code line 'IF testval1 > testval2 EXIT;' is removed from the program Read the following code carefully and fill in the blanks those follow. VAR num startval := 0; VR num endval := 25; VA num stepvalue := 1; VARm multval := 2; VAR num testval1 := 0; VAR num testval 2:= 200; FOR counterx FROM startval TO endval STEP stepvalue DO testval1 := testval1 + counterx * multval; PICK; DROP: IF testval1 > testval2 EXIT; ENDFOR a) The value of 'counterx' after fourth pick and drop operation will be A/ b) The maximum value of the variable 'testval1' can be A/ This loop will repeat for A times. d) The 'PICK' subroutine will execute for A times. e) The value of the variable 'testval1' will be A at the end of iteration when 'counterx' = 5. f) A Pick & Drop cycles possible in total using the above loop if the step value were initialized to 2. g) The Drop subroutine will be executed for A times if the code line 'IF testval1 > testval2 EXIT;' is removed from the program