Read this chapter 18 lab activity and write it in a short paragraph and following the same format and add 3 references. Title: Introduction: "Establishing Ohm's Law through Experiment" It is possible to "Establishing Ohm's Law through Experiment". Ohm's Law states that the electrical current (I) flowing in a circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change. Similarly, increasing the resistance of the circuit will lower the current flow if the voltage is not changed. The relationship between voltage, current, and resistance is described by Ohm's law. Ohm's law shows a linear relationship between the voltage and the current in an electrical circuit. Plus, the electrical current is affected by the voltage and resistance in a circuit. Ohm's Law comes with a set of three equations used to established and represent the relationship between voltage, electric current, and resistance. First we have the resistor's current I in amps (A) is equal to the resistor's voltage V in volts (V) divided by the resistance R in ohms (): I=VR . "V" represents the voltage drop of the resistor, measured in Volts (V). In some cases, Ohm's law uses the letter "E" to represent voltage. "E" denotes electromotive force. "I" represents the electrical current flowing through the resistor, measured in Amperes (A). "R" represents the resistance of the resistor, measured in Ohms (). Once the current and resistance is known, we can calculate the voltage. The voltage V in volts (V) is equal to the to the current I in amps (A) times the resistance R in ohms (): V=IR R in ohms () is equal to the voltage V in volts (V) divided by the current I in amps (A): R= VI . . Now, knowing the voltage and the current, we can calculate the resistance. The resistance Procedure: Go to http://phet.colorado.edu/simulations/sims.php?sim=Ohms_Law and click on Run Now. Once the simulation is running proceed by opening the "Electricity, Magnets, and Circuits Resistance in a Wire". Then begin answering the question to "Procedure Part I Wire Resistance:". Continue on to Procedure Part II: Ohm's Law: Electricity, Magnets, and Circuits Ohm's Law once complete. Then answer the following questions to the experiment. Results: You should show Amperes V=I*R 8.0 V 0.01 A 800 2.0 V .044 A 0.50 2.5 V .0058 A 430 6.9 V .069 A 100 6.4 V 0.0213 A 300 Discussions/Conclusions: The data collected in this simulation shows that it is possible to establish Ohm's Law through experiment. Part one of the experiment shows that as wire length (cm) increases, the resistance () increases but as wire area (cm2) increases, the resistance () decreases and as wire resistivity (cm) increases, the resistance () stays the same. A mA is milliamps, and 1000 milliamps is equal to one Ampere. Move the potential (volts) and resistance (ohms) sliders to observe the current (amps). Results showed that as voltage increases, current increases and as resistance increases, current decreases. The simulation shows milliamps but the table above shows the results in Amperes as instructed in the directions of the experiment. 1) Incandescent light bulbs have a very thin filament that glows when hot. These thin filaments have very high / low resistance. 2) If the 12V battery in your car operates a 25-amp car stereo the resistance of this stereo system would be 0.48 ohm. 3) If A "2D" Maglite flashlight runs on 3.0V the current through the bulb if resistance is 15 the results would show 0.20 amps. 4) How many volts must an iPod charger provide to charge an iPod using .85 Amps at 35 results in 29.75 V. 5) You need to buy a long extension cord to power a stereo at your spring break BBQ. Say you need 200 feet but you only have a 50 ft. cord that will work. Rationalizing that four such 50 ft. cords will do the job. Is this a good idea? Why or Why not? No, because the resistance will be 4 times higher which means the voltage drop will be 4 times higher and it may be enough drop that it will not be able to power the stereo. This is dangerous because it means the wire will generate more heat, which could melt the insulation and cause the wire to be exposed, creating a danger for shock and fire. Because your power source isn't changing, the voltage is fixed, but what you'll get is a 4x drop in current, which still means your stereo probably won't work.