Recall that a customer is considered to be very satisfed with hs or her XYZ Box video game system if the customer's composite score on the survey instrument is at least 42 One way to show that est es are ypealyvery sati ed s lo show nat ne mean of the population of al sat stacton ratings s at least 42. Letting this mean te ? in this enerse we wtsh to invest ate whether the santedros satsraction ratings prondes evdence to support the cam that ? exceeds 42 (and, therefore, is at least 42) For the sake or a prent we begin by assumng matu equ as 42 and le then attempt to use te sa pe o contraact this assum on in tavor of the conclusion that ? e ceeds 42 Recall that the mean of the sa pie of 65 satsta ton ratings isR-4295 and assume that ? the standard de aton of the populaton or al satisfaction ratings, is known to be 2 64 (a) Consider the sampling distribution of for random samples of 65 customer satisfaction ratings Use the properties of this sampling distribution to find the probability of observing a sample mean greater than or equal to 12 95 when we assume that equais 42 (Round o and p to 4 decimal places. Round z-scores to 2 decimal places. Do not round your intermediate PE 242 95)- (b) if u equali to 42, what percentage of all possible sample means are greater than or equal to 42 95? Since we have actualy that (1) u equal t a sample mean of 4295, is it more reasonable to believe b42 and we have observed a sample mean that is greater than or equal to 42 95 when ? equal to 42, or (2) that customers are typicaly very satistfied with we have observed a sample mean that is greater than or equal to the XYZ Box video game system? (Round your answer to 2 decimal places. Do not round your intermediate calculations. Input your answer to percent without percent sign.) %; conclude p (C1 to s Recall that a customer is considered to be very satisfed with hs or her XYZ Box video game system if the customer's composite score on the survey instrument is at least 42 One way to show that est es are ypealyvery sati ed s lo show nat ne mean of the population of al sat stacton ratings s at least 42. Letting this mean te ? in this enerse we wtsh to invest ate whether the santedros satsraction ratings prondes evdence to support the cam that ? exceeds 42 (and, therefore, is at least 42) For the sake or a prent we begin by assumng matu equ as 42 and le then attempt to use te sa pe o contraact this assum on in tavor of the conclusion that ? e ceeds 42 Recall that the mean of the sa pie of 65 satsta ton ratings isR-4295 and assume that ? the standard de aton of the populaton or al satisfaction ratings, is known to be 2 64 (a) Consider the sampling distribution of for random samples of 65 customer satisfaction ratings Use the properties of this sampling distribution to find the probability of observing a sample mean greater than or equal to 12 95 when we assume that equais 42 (Round o and p to 4 decimal places. Round z-scores to 2 decimal places. Do not round your intermediate PE 242 95)- (b) if u equali to 42, what percentage of all possible sample means are greater than or equal to 42 95? Since we have actualy that (1) u equal t a sample mean of 4295, is it more reasonable to believe b42 and we have observed a sample mean that is greater than or equal to 42 95 when ? equal to 42, or (2) that customers are typicaly very satistfied with we have observed a sample mean that is greater than or equal to the XYZ Box video game system? (Round your answer to 2 decimal places. Do not round your intermediate calculations. Input your answer to percent without percent sign.) %; conclude p (C1 to s
