Recall that the linearization of g(x) for x = a is given by L(x) = g(a) + g'(a)(x - a). The first step is to find g'(x) so that it can be used to find g'(a). For g(x) = V 1+ x = (1 + x)1/, we have g'(x ) = (1 + x) -6 -6 17 7 Therefore, at a = 0 we have g'(0) = 1/7 1/7 Step 2 Now, at a = 0, we have g(0) = Therefore, at a = 0, we have g ( x) = V 1 + x = g(0) + 9'(0)(x-0) We will now use this linear approximation to approximate v 0.95. We first need to rewrite \\ 0.95 in the form 1 + x, where x is a numerical value. Vo.95 = 1 + Submit Skip (you cannot come back)