Recently, the number of airline companies that offer in-flight Wi-Fi service to passengers has increased. However, it is estimated that only 8% of the passengers who have Wi-Fi available to them are willing to pay for it. Suppose the largest provider of airline Wi-Fi service, would like to test this hypothesis by randomly sampling 400 passengers and asking them if they would be willing to pay $4.95 for 90 minutes of onboard Internet access. Suppose that 36 passengers indicated they would use this service. Using alpha equals 0.05, complete parts a and b below.

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Part 1 a. What conclusions can be drawn about the proportion of airline passengers willing to pay for onboard Wi-Fi service? Determine the null and alternative hypotheses. Choose the correct answer below.

Upper H 0 : p equals 0.08

Upper H 1 : p not equals 0.08

Your answer is correct.

Determine the critical value(s) of the test statistic.

z Subscript alpha equals 1.960, -1.960

Calculate the test statistic. z Subscript p equals. 74

Determine the proper conclusion. Choose the correct answer below.

A.

Do not reject Upper H 0, and conclude that the proportion of airline passengers willing to pay for onboard Wi-Fi service could be 8%.

All above is correct. Need to help with the below:

b. Determine the p-value for this test.

p-value equals

enter your response here

I AM CONFUSED HOW TO COME UP WITH THE P-VALUE. I used NORM.S.DIST(.74,TRUE) and it states the answer is wrong.