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Recurrence relation using substitution method T(n)=3T(3n)+n,T(1)=3 T(n)=3T(3n)+3n,T(1)=1

Recurrence relation using substitution method
T(n)=3T(3n)+n,T(1)=3 T(n)=3T(3n)+3n,T(1)=1

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