Redo example 22.2 using values as given. As per drawing ql and q2 are located (placed) at the base of a cube midway of a and q3 is now located dead center of the cube. Find the Force excreted on q3 by ql and q2. Consider three point charges located at the corners of a right triangle as shown in the figure, where q1 = q3 = 5.00 pC, q2 = 2.00 \"C, and a = 0.100 m. Find the resultant force exerted on q3. (r / 2.00 x106 C)(5.00x10% C) F23 = ke 192 93 = 8.988 x 109 N . m2 /C2 = 8.99 N a 2 (0.100 m) 191 93 F13 = ke (8.988x109 N . m2 /C2 5.00x10 C)(5.00x10 C) =11.2N 2 (0.100 m) F13x = (11.2 N)cos 45.00 = 7.94 N F 13 a FBY = (11.2 N ) sin 45.0 = 7.94 N 92 93 Fox = F13x + F23, = 7.94 N +(-8.99 N)=-1.04 N a Fay = FiBy + F23) = 7.94 N+0 =7.94 N V2a r F, = (-1.041 + 7.94j) N + X