Refer to this data table: Specific heat of: Molar heat of fusion of ice = 6.01 kJ/mol. ice = 2.03 J/g C. Molar heat of vaporization of water = 40.79 kJ/mole steam = 1.99 J/g C. water = 4.184 J/g C. Calculate the heat in kJ required to transform 433 grams of ice at -70.0 degrees C to liquid water at 50.0 degrees C.

613 kJ

5.04 kJ

3.28 kJ

9.53 x 10 ^-1 kJ

8.93 kJ

1.91 x 10 ² kJ

297 k J

26.7 kJ