Researchers collected information on the body parts of a new species of frog. The thumb length for the female frog has a mean of 5.43 mm and a standard deviation of 0.78 mm. Let x denote thumb length for a female specimen.

a. Find the standardized version of x.

b. Determine and interpret thez-scores for thumb lengths of 6.8 mm and 5.1 mm. Round your answers to two decimal places.

a. Find the standardized version of x.

z=nothing

(Do not simplify. Use integers or decimals for any numbers in the expression. Do notround.)

b. Determine and interpret thez-scores for thumb lengths of 6.8 mm and 5.1 mm. Round your answers to two decimal places.

Determine and interpret thez-score for a thumb length of 6.8 mm.

Thez-score for a thumb length of 6.8 is nothing. This is nothing standard deviations

(Round to two decimal places asneeded.)

Determine and interpret thez-score for a thumb length of 5.1 mm.

Thez-score for a thumb length of 5.1 is nothing. This is nothing standard deviations

(Round to two decimal places asneeded.)