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Researchers investigated the failure time of bearings treated with 5 different compounds.As part of the procedure, they carried out an ANOVA, testing the null hypothesis

Researchers investigated the failure time of bearings treated with 5 different compounds.As part of the procedure, they carried out an ANOVA, testing the null hypothesis that all 5 compounds have the same true mean failure time.In the ANOVA, they found a p-value of 0.002, and decided to apply the Tukey procedure to find confidence intervals for the pairwise differences in means at a family-wise confidence level of 95%.The results of the Tukey procedure are given below.("lower" is the lower bound of the interval, "upper" is the upper bound.)

How many of these pairwise differences are statistically significant?(No calculations required!)

 lwr upr B-A -10.3234907 1.037491 C-A -7.7374907 3.623491 D-A -6.5754907 4.785491 E-A -1.6674907 9.693491 C-B -3.0944907 8.266491 D-B -1.9324907 9.428491 E-B 2.9755093 14.336491 D-C -4.5184907 6.842491 E-C 0.3895093 11.750491 E-D -0.7724907 10.588491 

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