Resources Ly Give Up? Check Answer 18 of 20 Questions Assignment Score: 0% 9 Hint Press Esc to exit full screen 10 Question 0% 0 of co Attempts 20 A cube of side a is cut out of another cube of side b that has a b 11 Question 0% uniform density, as shown in the figure. 0 of co Attempts @Macmillan Learning Express the center of mass rom of the structure using ijk unit vector notation. Set the origin at the front bottom-left corner 12 Question 0% 0 of co Attempts of the figure where the dashed lines intersect. 13 Question 0% a 0 of co Attempts TOM = 14 Question 0% 0 of co Attempts Question Credit: OpenStax University Physics v1 15 Question 0% 0 of co Attempts 16 Question 0% 0 of co Attempts 17 Question 0% 0 of co Attempts 18 Question 0% 0 of . Attempts 19 Question 0 of co Attempts 20 Question 0% 0 of co Attempts19 of 20 Questions Assignment Score: 0% Resources Ly Give Up? Hint Check Answer Press Esc to exit full screen 10 Question 0% 0 of co Attempts . Suppose a flat piece of plastic of uniform density p is in the b AV 11 Question 0% shape of a right triangle. The legs of the triangle are given as 0 of co Attempts a and b. Macmillan Learning 12 Question Where is the center of mass of this triangle? Using the 0% 0 of co Attempts coordinate system given, enter the coordinates of the center of mass in terms of a and b. X 13 Question 0% 0 of co Attempts a The x-coordinate XCM of the center of mass is 14 Question 0% 0 of co Attempts 15 Question 0% XCM = 0 of co Attempts 16 Question 0% The y-coordinate yCM of the center of mass is 0 of co Attempts 17 Question 0% 0 of co Attempts yCM = 18 Question 0% 0 of co Attempts 19 Question 0% 0 of co Attempts 20 Question 0% 0 of co AttemptsCheck Answer 20 of 20 Questions Assignment Score: 0% Resources Ly Give Up? Hint Press Esc to exit full screen 10 Question 0% 0 of co Attempts A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not 11 Question 0% interact with any objects outside of the system. Find the velocity v4 of particle 4 at 1 = 2.51 s given the details for the motion 0 of co Attempts of particles 1, 2, and 3. Macmillan Learning 12 Question 0% particle 1: m1 = 1.21 kg, v1 (t) = (6.31 m/s) + (0.365 m/s2) x t 0 of co Attempts particle 2: m2 = 2.69 kg, U2 (1) = (9.15 m/s) + (0.357 m/s2 ) x t 13 Question 0% 0 of co Attempts particle 3: my = 4.25 kg, v3 (t) = (7.43 m/s) + (0.195 m/s? ) x t particle 4: m4 = 4.43 kg 14 Question 0% 0 of co Attempts 15 Question 0% 0 of co Attempts UA = m/s 16 Question 0% 0 of co Attempts 17 Question 0% 0 of co Attempts 18 Question 0 of co Attempts 19 Question 0 of co Attempts 20 Question 0% 0 of co Attempts