rk E Homework HW Score: 69 13% 8 99 of 13 11/10/202 de he Critical Values for the t Distribution (Page 1) X Save Question lis confidence interval at 2 Critical Values of t 2/20 Question 1 For a particular number of degrees of freedom, entry represents 2/13 the critical value of t corresponding to the cumulative probability (1 - a) and a specified upper-tail area (a). 0 3.75 Question 2 Cumulative Probabilities nlim 0.75 0.90 0.95 0.975 0.99 0.995 Degrees of Upper-Tail Areas Question 3 Freedom 0.25 0.10 0.05 0.025 0.01 0.005 stion 1.0000 3.0777 6.3138 12.7062 31.8207 63.6574 0.8165 1.8856 2.9200 4.3027 6.9646 9.9248 0.7649 1.6377 2.3534 3.1824 4.5407 5.8409 X Question 4 0.7407 1.5332 2.1318 2.7764 YOUAWN 3.7469 4.6041 0.7267 1.4759 2.0150 2.5706 3.3649 4.0322 0.7176 1.4398 1.9432 2.4469 3.1427 3.7074 7/1) 0.7111 1.4149 1.8946 2.3646 2.9980 3.4995 Question 5 0.7064 1.3968 1.8595 2.3060 2.8965 3.3554 "1) 0.7027 1.3830 1.8331 2.2622 2.8214 3.2498 10 0.6998 1.3722 1.8125 2.2281 2.7638 3.1693 0.6974 1.3634 1.7959 2.2010 2.7181 3.1058 Question 6 Question 7 Print Done view an example Get more help - Clear an Check answer tistic Help me solve this licy 64 DEC O GBusiness Statistics | Stat 2000 CTRA[31452] ants Debora Pierre 12/13/22 4:32 PM (? ik E Homework HW Score: 69 13% 8 99 of 13 11/10/202 Critical Values for the t Distribution (Page 1)] X Save he Question li confidence interval GE 0.6974 1.3634 1.7959 2.2010 2.7181 3.1058 0.6955 1.3562 1.7823 2.1788 13 2.6810 3.0545 t 2 0.6938 1.3502 1.7709 2.1604 2.6503 3.0123 14 0.6924 1.3450 1.7613 2.1448 2.6245 2.9768 20 Question 1 15 0.6912 1.3406 1.7531 2.1315 2.6025 2.9467 16 0.6901 1.3368 1.7459 2.1 199 2.5835 2.9208 13 17 0.6892 1.3334 1.7396 2.1098 2.5669 2.8982 18 0.6884 1.3304 1.7341 2.1009 2.5524 2.8784 75 Question 2 19 0.6876 1.3277 1.7291 2.0930 2.5395 2.8609 20 0.6870 1.3253 1.7247 2.0860 2.5280 2.8453 lim 21 0.6864 1.3232 1.7207 2.0796 2.5177 2.8314 22 0.6858 1.3212 1.7171 2.0739 2.5083 2.8188 Question 3 23 0.6853 1.3195 1.7139 2.0687 2.4999 2.8073 tion 24 0.6848 1.3178 1.7109 2.0639 2.4922 2.7969 25 0.6844 1.3163 1.7081 2.0595 2.4851 2.7874 26 0.6840 1.3150 1.7056 2.0555 2.4786 2.7787 X Question 4 27 0.6837 1.3137 1.7033 2.0518 2.4727 2.7707 28 0.6834 1.3125 1.7011 2.0484 2.4671 2.7633 29 0.6830 1.3114 1.6991 2.0452 2.4620 2.7564 30 0.6828 1.3104 1.6973 2.0423 2.4573 2.7500 /1) Question 5 31 0.6825 1.3095 1.6955 2.0395 2.4528 2.7440 32 0.6822 1.3086 1.6939 2.0369 2.4487 2.7385 33 0.6820 1.3077 1.6924 2.0345 2.4448 2.7333 34 0.6818 1.3070 1.6909 2.0322 2.441 1 2.7284 35 0.6816 1.3062 1.6896 2.0301 2.4377 2.7238 Question 6 Question 7 Print Done stic Help me solve this View an example Get more help Clear all Check answer cylHomework HW Score: 69 13% 8 99 of 13 11/10/202 Critical Values for the t Distribution (Page 1) X Sa Question lis 30 0.6828 1.3104 1.6973 2.0423 2.4573 2.7500 confidence 31 0.6825 1.3095 1.6955 2.0395 2.4528 32 2.7440 0.6822 1.3086 1.6939 2.0369 2.4487 2.7385 33 0.6820 1.3077 1.6924 2.0345 2.4448 2.7333 Question 1 34 0.6818 1.3070 1.6909 2.0322 2.4411 2.7284 35 0.6816 1.3062 1.6896 2.0301 2.4377 2.7238 36 0.6814 1.3055 1.6883 2.028 2.4345 2.7195 37 0.6812 1.3049 1.6871 2.0262 2.4314 2.7154 Question 2 38 0.6810 1.3042 1.6860 2.0244 2.4286 2.7116 39 0.6808 1.3036 1.6849 2.0227 2.4258 2.7079 40 0.6807 1.3031 1.6839 2.021 1 2.4233 2.7045 41 0.6805 1.3025 1.6829 2.0195 2.4208 2.7012 Question 3 42 0.6804 1.3020 1.6820 2.0181 2.4185 2.6981 43 0.6802 1.3016 1.681 1 2.0167 2.4163 2.6951 44 0.6801 1301 1 1.6802 2.0154 2.4141 2.6923 45 0.6800 1.3006 1.6794 2.0141 2.4121 2.6896 0.6799 Question 4 46 1.3002 1.6787 2.0129 2.4102 2.6870 47 0.6797 1.2998 1.6779 2.0117 2.4083 2.6846 48 0.6796 1.2994 1.6772 2.0106 2.4066 2.6822 Degrees of 0.25 0.10 0.05 0.025 0.01 0.005 Question 5 Freedom Upper-Tail Areas 0.75 0.90 0.95 0.975 0.99 0.995 Cumulative Probabilities Question 6 Question 7 Print Done Help me solve this view an example Get more help Clear air Check anBusiness Statistics | Stat 2000 CTRA[31452] Debora Pierre 12/13/22 4:33 PM Do Homew Homework HW Score: 69 13% 8 99 of 13 11/10/202 Critical Values for the t Distribution (Page 2) X Save uestion li confidence interval Cumulative Probabilities Question 1 0.75 0.90 0.95 0.975 0.99 0.995 Degrees of Upper-Tail Areas Freedom 0.25 0.10 ).05 0.025 0.01 0.005 Question 2 49 0.6795 1.2991 1.6766 2.0096 2.4049 2.6800 50 0.6794 1.2987 1.6759 2.0086 2.4033 2.6778 0.6793 1.2984 1.6753 2.0076 2.4017 2.6757 0.6792 1.2980 1.6747 2.0066 2.4002 2.6737 Question 3 0.6791 1.2977 1.6741 2.0057 2.3988 2.6718 54 0.6791 1.2974 1.6736 2.0049 2.3974 2.6700 55 0.6790 1.2971 1.6730 2.0040 2.3961 2.6682 Inco 56 0.6789 1.2969 1.6725 2.0032 2.3948 2.6665 Question 4 0.6788 1.2966 1.6720 2.0025 2.3936 2.6649 0.6787 1.2963 1.6716 2.0017 2.3924 2.6633 0.6787 1.2961 1.671 1 2.0010 2.3912 2.6618 0.6786 1.2958 1.6706 2.0003 2.3901 2.6603 0.6785 1.2956 1.6702 1.9996 Question 5 2.3890 2.6589 0.6785 1.2954 1.6698 1.9990 2.3880 2.6575 0.6784 1.2951 1.6694 1.9983 2.3870 2.6561 0.6783 1.2949 1.6690 1.9977 2.3860 2.6549 0.6783 1.2947 1.6686 1.9971 2.3851 2.6536 Question 6 Question 7 Print Done lelp me solve this view an example Get more nelp Clear am Check answerBusiness Statistics | Stat 2000 CTRA[31452] Debora Pierre 12/13/22 4:33 PM ? Homework HW Score: 69 13% 8 99 of 13 11/10/202 Critical Values for the t Distribution (Page 2) X Save Question li 0.6782 1.2945 1.6683 confidence interval 1.9966 2.3842 2.6524 198 0.6782 1.2943 1.6679 1.9960 2.3833 2.6512 68 0.6781 1.2941 1.6676 1.9955 2.3824 2.6501 69 0.6781 1.2939 1.6672 1.9949 2.3816 2.6490 Question 1 70 0.6780 1.2938 1.6669 1.9944 2.3808 2.6479 71 0.6780 1.2936 1.6666 1.9939 2.3800 2.6469 72 0.6779 1.2934 1.6663 1.9935 2.3793 2.6459 73 0.6779 1.2933 1.6660 1.9930 2.3785 2.6449 Question 2 74 0.6778 1.2931 1.6657 1.9925 2.3778 2.6439 75 0.6778 1.2929 1.6654 1.9921 2.3771 2.6430 76 0.6777 1.2928 1.6652 1.9917 2.3764 2.6421 77 0.6777 1.2926 1.6649 1.9913 2.3758 2.6412 Question 3 78 0.6776 1.2925 1.6646 1.9908 2.3751 2.6403 79 0.6776 1.2924 1.6644 1.9905 2.3745 2.6395 80 0.6776 1.2922 1.6641 1.9901 2.3739 2.6387 81 0.6775 1.2921 1.6639 1.9897 2.3733 2.6379 0.6775 1.2920 1.6636 1.9893 2.3727 2.6371 Question 4 83 0.6775 1.2918 1.6634 1.9890 2.3721 2.6364 84 0.6774 1.2917 1.6632 1.9886 2.3716 2.6356 85 0.6774 1.2916 1.6630 1.9883 2.3710 2.6349 86 0.6774 1.2915 1.6628 1.9879 2.3705 2.6342 Question 5 87 0.6773 1.2914 1.6626 1.9876 2.3700 2.6335 88 0.6773 1.2912 1.6624 1.9873 2.3695 2.6329 89 0.6773 1.291 1 1.6622 1.9870 2.3690 2.6322 90 0.6772 1.2910 1.6620 1.9867 2.3685 2.6316 Question 6 Question 7 Print Done Clear all Check answer Help me solve this View an example Get more nerpG Q 8 0 mylab.pearson.com Business Statistics | Stat 2000 CTRA[31452] lents Debora Pierre 12/13/22 4:33 PM Do Homey rk E Homework HW Score: 69 13% 8 99 of 13 11/10/202 X Save le he Critical Values for the t Distribution (Page 2) Question li confidence interval 0.6774 1.2915 1.6628 1.9879 2.3705 2.6342 0.6773 1.2914 1.6626 1.9876 2.3700 SS 2.6335 it 2 0.6773 1.2912 1.6624 1.9873 2.3695 89 2.6329 0.6773 1.2911 1.6622 1.9870 2.3690 2.6322 Question 1 90 0.6772 1.2910 1.6620 1.9867 2.3685 2.6316 91 0.6772 1.2909 1.6618 1.9864 2.3680 2.6309 13 92 0.6772 1.2908 1.6616 1.9861 2.3676 2.6303 93 0.6771 1.2907 1.6614 1.9858 2.3671 2.6297 75 Question 2 94 0.6771 1.2906 1.6612 1.985 2.3667 2.6291 95 0.6771 1.2905 1.6611 1.9853 2.3662 2.6286 im 96 0.6771 1.2904 1.6609 1.9850 2.3658 2.6280 97 0.6770 1.2903 1.6607 1.9847 2.3654 2.6275 Question 3 98 0.6770 1.2902 1.6606 1.9845 2.3650 2.6269 99 0.6770 1.2902 1.6604 1.9842 2.3646 2.6264 100 0.6770 1.2901 1.6602 1.9840 2.3642 2.6259 110 0.6767 1.2893 1.6588 1.9818 2.3607 2.6213 X Question 4 120 0.6765 1.2886 1.6577 1.9799 2.3578 2.6174 0.6745 1.2816 1.6449 1.9600 2.3263 2.5758 Degrees of 0.25 0.10 0.05 0.025 0.01 0.005 Freedom Question 5 Upper-Tail Areas 0.75 0.90 0.95 0.975 0.99 0.995 Cumulative Probabilities Question 6 Question 7 Print Done Help me solve this View an example Get more help Clear all Check answerBusiness Statistics | Stat 2000 CTRA[31452] Homework: Stat 2000 HW_CH08 HW Score: 69.13%, 8.99 of 13 E 11/10/2022 Question 4, 8.2.11 points Points: 0 of 1 Save Question list K If X = 64, S =7, and n = 25, and assuming that the population is normally distributed, construct a 95% confidence interval estimate of the population mean, H. Click here to view page 1 of the table of critical values for the t distribution. Click here to view page 2 of the table of critical values for the t distribution. Question 1 SHS Question 2 (Round to two decimal places as needed.) Question 3 X Question 4 Question 5 Question 6 Question 7 Clear all Check answe Help me solve this View an example Get more help -Do Hom ework E Homework: Stat 2000 HW CH07 Question 1, 7.2.1-T HW Score: 84%, 6.72 of 8 11/01/2022 Part 4 of 4 points Points: 0.75 of 1 Save s made he Given a normal distribution with u = 101 and o = 15, and given you select a sample of n = 9, complete parts (a) Question list K through (d). Stat 2 12/20 Question 1 a. What is the probability that X is less than 90? 12/13 P(X 101.2) = 1841 (Type an integer ) decimal rounded to four decimal places as needed.) Question 5 d. There is a 64% chance that X is above what value? X =0 Question 6 (Type an integer or decimal rounded to two decimal places as needed.) Question 7 ss Statistic cy Policy | Help me solve this View an example Get more help - Clear all Check answer DEC 3 64 13 tv 4 O G X Faments Debora Pierre 12/13/22 4:34 PM ? Do Homewor rk E Homework: Stat 2000 HW CH07 Question 3, 7.2.5-T HW Score: 84%, 6.72 of 8 11/01/2022 Part 5 of 5 points Points: 0.67 of 1 Save de he Question list K The amount of water in a bottle is approximately normally distributed with a mean of 2.55 liters with a standard deviation of 0.025 liter. Complete parts (a) through (e) below. at 2 2/20 % Question 1 w. 11 a SailINIc VI + MULLIGO 10 WIIGL IS LIG PIVUAVIIILy WIL LIG SaIIIPIG IIIcall allVuIll WILLall IGu 16 1650 Wal1 4.JU liters? 2/13 0.055 (Round to three decimal places as needed.) 4% ( Question 2 c. If a sample of 25 bottles is selected, what is the probability that the sample mean amount contained is less than 2.53 nlim liters ? Question 3 0.000 (Round to three decimal places as needed.) estio Inco d. Explain the difference in the results of (a) and (c). 5/1) Question 4 Part (a) refers to an individual bottle, which can be thought of as a sample with sample size 1 . Therefore, the standard error of the mean for an individual bottle is 5 times the standard error of the sample in (c) with sample size 25. This leads to a probability in part (a) that is larger than the probability in part (c). Question 5 Type integers or decimals. Do not round.) e. Explain the difference in the results of (b) and (c). The sample size in (c) is greater than the sample size in (b), so the standard error of the mean (or the standard deviation Question 6 of the sampling distribution) in (c) is than in (b). As the standard error values become more concentrated around the mean. Therefore, the probability that the sample mean will fall close to the population mean will always when the sample size increases. Question 7 tistic icy Help me solve this View an example Get more help - Clear all Check answer 48 64 DEC atv O x F 12