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Run the algorithm for n = 3 2 and for each of the following cases: ( 1 ) Worst - case data input; ( 2

Run the algorithm for n =32 and for each of the following cases:
(1) Worst-case data input; (2) Best-case data input; (3) Random data input. (Performance on random
data represents average-case.)
For each case, print n, input array, output array (sorted data), and the number of key-comparisons. Does
the number of key-comparisons agree with the theoretical values? Theoretically, the worst-cse number of
key comparisons is (n2 n)/2, and the average number is (n2 n)/4, which is half of the worst-case

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