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S( 3x. 5)(1-x2) ) dx - (( 3 ) 415) du LET U = 1 - X2 THEN du =. = - 2X ( 3

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S( 3x. 5)(1-x2) ) dx - (( 3 ) 415) du LET U = 1 - X2 THEN du =. = - 2X ( 3 )du = ( -2 ) (- 2x ) dx ( 3) du = (3x) dx Thomas thinks that the problem f(3x*(1-x^2)^(1/5))dx is too difficult to do. Joe helps Thomas with "u" substitution, setting up the problem as shown above. Joe shows Thomas that the problem can be simplified to the form f((-3/2)*u^(1/5))du. What is the result of the integration involving "u" ? O A(u) = (-3/2)*u^(6/5) + C O A(u) = (-5/4)"u^(6/5) + C O A(u) = (-3/10)"u^(-4/5) + C O A (U) = (-4/5)"u^ (6/5 ) + C

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