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Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator
Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. i Click the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? O A. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O B. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. - X O C. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. Calculator results O D. Reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. One-way ANOVA F =9.7775099491 p = 5.3765538E - 4 Factor df = 2 SS = 1456.01943 I MS = 728.009717 One-way ANOVA 1 MS = 728.009717 Error df = 30 SS = 2233.72736 MS = 74.4575787 Sxp = 8.62888050 Print DoneMale BMI Female BMI H1 H2 Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for 40 both parts n 40 x 27.4681 24.6769 $ 7.106303 4.029399 a. Test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? OA. HO: H1 2 H2 OB. HO: H1 = H2 H1: My
H2 O C. HO: H1 # H2 OD. HO: H1 = H2 H1: H1
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