Question
SampleSize 20 PopulationStandardDeviation 0.18 SampleMean 8.3700 SampleStandardDeviation 0.1895 SampleSize 20 SampleMean 8.3700 ConfidenceInterval ConfidenceCoefficient 0.99 ConfidenceInterval LowerLimit ConfidenceCoefficient 0.99 UpperLimit LowerLimit UpperLimit HypothesisTest HypothesizedValue 8.3
| SampleSize | 20 | PopulationStandardDeviation | 0.18 | |
| SampleMean | 8.3700 | |||
| SampleStandardDeviation | 0.1895 | SampleSize | 20 | |
| SampleMean | 8.3700 | |||
| ConfidenceInterval | ||||
| ConfidenceCoefficient | 0.99 | ConfidenceInterval | ||
| LowerLimit | ConfidenceCoefficient | 0.99 | ||
| UpperLimit | LowerLimit | |||
| UpperLimit | ||||
| HypothesisTest | ||||
| HypothesizedValue | 8.3 | HypothesisTest | ||
| TestStatistic | HypothesizedValue | 8.3 | ||
| p-value(LowerTail) | 0.9425 | TestStatistic | ||
| p-value(UpperTail) | p-value(LowerTail) | 0.9591 | ||
| p-value(TwoTail) | p-value(UpperTail) | |||
| p-value(TwoTail) |
Walmart claims the average time waiting in their checkout lines is 8.3 minutes. A random sample of 20 Walmart shoppers is taken and their time waiting in the checkout line is recorded in Excel. Based on this paragraph of text, use the correct excel output above to answer the following question. For the 99% confidence interval, find the upper (i.e., right) endpoint.
The answer is 8.4912 but i need to step by step how to find the values. Dont skip any steps also include how to find the Z score for the value
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Several Real Variables
Authors: Shmuel Kantorovitz
1st Edition
3319279564, 9783319279565
