Take a slab waveguide of thickness d bounded on either side by the cladding medium. Find the thickness dTE1 cutoff below where the fundamental TEO mode is the only transverse electric (TE) mode supported, i.e. there is no TE1 guided mode solution. Now set the slab thickness to be 80% of this thickness, i.e. 0.8dTE1 cutoff. Generate a plot showing the transverse electric field Ex as a function of distance normal to the layer (y) for the fundamental TE mode and determine the associated effective index of the mode. Similarly, keeping the same slab thickness 0.8dTE1 cutoff, generate a plot showing the transverse magnetic field Hx as a function of distance normal to the layer (y) for the fundamental TM mode and determine the associated effective index of the mode. Which fundamental mode has the larger effective index? the wavelength as 1480 nm and the waveguide is completely immersed in a cladding of refractive index 1.4 5 on all relevantsides. The refractive of the coremediumis taken to be (2.5+76/100)-3.26 matlab, python are available.