SAT scores = q bases = n of nsam erif ledsl bnis mapofaid vilidsdong andf wsid .DE All sections of the test are known to be normally distributed with mean of approximately 1083 and standard deviation of only o = 194. (a) Draw a normal curve with the parameters labeled. asD = 194 - 889 889 69 5 J = mean= 1083 -20.0 1083 (b) Shade the region that represents the proportion of test takers who scored less than 800. (c) Suppose the area under the normal curve to the left of X = 800 is 0.0723. Provide two interpretations of this result. sriW . Mq S bnis SI neewied evinis lliw nslainset erli isit asisle debivong femininA .& 1 . fretsl 10 at: is evinis lliw asioindoet edi fads vilidsdorq 2 . ons enolisiveb bisbasta , nsem erli isdad .81 = o bns Ost = 4 dilw svivo ismon s wsid .SE .atnlog noifooltni find a park 18