Scenario 6

A survey of families revealed that 58% of all families eat turkey at holiday meals, 44% eat ham, and 16% have both turkey and ham to eat at holiday meals.

Answer questions 25 - 28 based on scenario 6:

Question 25 (1 point)

Based on scenario 6, what is the probability that a family selected at random had neither turkey nor ham at their holiday meal?

Question 25 options:

a)

58%

b)

44%

c)

28%

d)

14%

Question 26 (1 point)

Based on scenario 6, what is the probability that a family selected at random had only ham without having turkey at their holiday meal?

Question 26 options:

a)

58%

b)

44%

c)

28%

d)

14%

Question 27 (1 point)

Based on scenario 6, what is the probability that a randomly selected family having turkey had ham at their holiday meal?

Question 27 options:

a)

58%

b)

44%

c)

28%

d)

14%

Question 28 (1 point)

Based on scenario 6, what can we say about the events of families having a dinner of turkey and / or ham?

Question 28 options:

a)	The events are disjoint events since not all families had both turkey and ham

b)	The events are disjount events since an unequal number of families had turkey or ham

c)	The events are not disjoint since some families had turkey and ham

d)	The events are not disjoint since most families had turkey