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Scenario 6.5: The increased use of medical imaging technologies, such as CT scans, has raised concerns about radiation exposure to patients. To help reduce overall

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Scenario 6.5: The increased use of medical imaging technologies, such as CT scans, has raised concerns about radiation exposure to patients. To help reduce overall exposure, researchers are investigating methods of reducing radiation doses. The researchers wanted to determine if the tube voltage CT scans can result in different radiation dose when compared to normal CT scans for abdominal imaging. The researchers randomly select 30 patients needing CT scans of the abdomen. The patients are then randome allocated to either a normal CT scan or a low tube voltage CT scan. (Radiation dose was measured in mGy.) Group N Mean {mGy} Std. Deviation Std. Error Mean 52p Low VDltage (sample 2) --__ Question 54 2 pts For scenario 6.5, match bellow to select the correct null and alternative hypotheses. HO: [ Choose ] Ha: [ Choose ] Question 55 2 pts Calculate the test statistic for scenario 6.5. Give your answer using 2 decimal points. Question 56 1 pts Give the critical value for scenario 6.5. Give your answer using 2 decimal points.Question 57 2 pts Conclusion for scenario 6.5 based on the critical value method: Based on the critical value method we see that the calculated statistics is (|=|less than|more than|smaller than|bigger than|larger than|same as) the critical value so we (fail to reject | reject | accept | approve )' then null hypothesis and conclude that there {is|are|is not|is no|are no|exist|exist no|exist not) signicant difference of the means for normal and low voltage. Please include no spaces or other symbols before or after your answers. Calculate the 95% CI for scenario 6.5 in the form of (LB,UB)_ Give the lower bound LB and the upper bound UB of this interval in the following two questions below using 2 decimal points. Question 58 1 pts LB: Question 59 1 pts UB= Question 60 2 pts Conclusion for scenario 6.5 based on the calculated CI: Based on the confidence interval method we see that the 95% Cl (captures|does not capture includes|does not include|... ) the value so we (fail to reject | reject | accept | approve ) then null hypothesis and conclude that there (is|are is not|is no|are no|exist|exist no|exist not) significant difference between the sample and population mean for lung cancer. Please include no spaces or other symbols before or after your answers

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