Question
Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.3 times
Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.3 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191 x 1023 kg rmars = 3.397 x 106 m G = 6.67428 x 10-11 N-m2/kg2
What is the force of attraction between Mars and the satellite?
What speed should the satellite have to be in a perfectly circular orbit?
How much time does it take the satellite to complete one revolution?
What should the radius of the orbit be (measured from the center of Mars), if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
Step by Step Solution
There are 3 Steps involved in it
Step: 1
To solve this problem we can use the universal law of gravitation centripetal force equation and orbital period formula Given data Mass of Mars M mmars 64191 x 1023 kg Radius of Mars R rmars 3397 x 10...Get Instant Access to Expert-Tailored Solutions
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Step: 2
Step: 3
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