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SECTION II: Q2). A person sitting near a window in a multi-storey building sees a rock passing upward with a vertical speed of 14 m/s.

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SECTION II: Q2). A person sitting near a window in a multi-storey building sees a rock passing upward with a vertical speed of 14 m/s. Take the upward direction as the positive direction, and also assume that the person sitting near the window is 18 m above the street level from where the rock was thrown: Drag and drop answer choices to their matching answer. Answer Choices: Which equation will allow 0.96 s you to directly calculate the initial velocity u, of the rock? Ay v.At + Ja (At) What was the rock's initial speed? 0.94 s What altitude did the rock reach? - 23.4 m/'s Which equation can you 27.4 m use to find out when the rock thrown (i.e., time it took for the rock to pass by the window from 23.4 m/s

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