- See the problem below. With wind force (F) varying from 0 to 120 lbs, graph the parallel and perpendicular resultant forces as a function of the force due to the wind. (Note that for a force of F = 80 lb and an angle of 35, the resultant force parallel {that is pushing the boat] is 45.9 lbs and the resultant force that is perpendicular (trying to tip the boat] is 65.5 lbs]. The graph should have two yaxes one that is the resultant force parallel and the other the resultant force that is perpendicular. The xeaxis should vary from 0 to 120 lbs. - For a constant wind force of 80 lbs, graph the resultant parallel and perpendicular forces as the angle varies from 0" to 60. The graph should have two v-axes 7 one that is the resultant force parallel and the other the resultant force that is perpendicular. The xeaxis should vary from 0 to 60. Which angle pushes the boat forward with the greatest resultant force? 211. The wind is deected by the sail of a boat such that it exerts a resultant force of F = 80 lb perpendicular to the sail. Resolve this force into two components, one parallel and one perpendicular to the keel cm of the boat. Note: The ability to sail into the wind is known as tacking, made pos sible by the force parallel to the boat's keel. The perpendic- ular cornponent tends to tip the boat 01' push it over