Question
SETS Let T be a set, let x be a set of subsets of T , and let Y={S^(C)subeT:Sinx} . Show that the mapping f
SETS\ Let
T
be a set, let
x
be a set of subsets of
T
, and let
Y={S^(C)subeT:Sinx}
. Show that the mapping
f
that maps each
Sin
x
to
S^(C)inY
is a bijection.\ Prove the following claim by way of contradiction. For every set
S
, if
|S|, then for every two subsets
T,RsubeS
such that
T
and
R
are disjoint it holds that
|T|+|R|.\ When proving the claim, state explicitly and fully what is the assumption that you are making towards a contradiction.\ (This question is intended to hammer in the point about proofs by contradiction that was explained in Piazza.)\ Recall that, as we learned in class, if
S_(1)
and
S_(2)
are disjoint sets, then
|S_(1)\\\\cup S_(2)|=|S_(1)|+|S_(2)|
. Prove a generalization for multiple sets: If
n>=2
sets
S_(1),S_(2),dots,S_(n)
are pairwise-disjoint (i.e., for each distinct
i,jin[n]
it holds that
S_(i)
and
S_(j)
are disjoint), then\
|S_(1)\\\\cup S_(2)\\\\cup dots\\\\cup S_(n)|=\\\\sum_(iin[n]) |S_(i)|
\ (Inclusion-exclusion principle, special case.) Prove that for any two sets
S
and
T
it holds that
|S\\\\cup T|=|S|+|T|-|S\\\\cap T|
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