$//$ shift$\_$digits$($n$)$ returns the number consisting of the decimal digits of n $//$ shifted forward by $1,$ so $123$ becomes $234($the digit $9$ does not get changed$)//$ requires: $0<=$ n $<1,000,000,000$ int shift$\_$digits$($int n$)$; Use the following main function exactly: int main$($void$)\{$ int n $=0$; scanf$("\%$d$",$ &n$)$; printf$("\%$d

$",$ shift$\_$digits$($n$))$; $\}$