Short Answer 15. A 10 m long beam is in equilibrium, somewhere near the surface of the Earth. The beam is held up by two ideal ropes, one rope is 0.7 m from the left end, and the other is 8.5 m from the left end. The tension in the left rope is 1438 . The tension in the right rope is 2476 N. A 100 person is standing slightly to the right of ce t of center of the beam. FTL= 1438 N FTR=2476 N 0.7m 8.5 m Beam 10 m Earth a) What is the mass of the person? 100 kg, (b) What is the magnitude of the total force acting on the beam? 12476-1438 = 10382 + 980IN 103 82 N - 9803N (c) What is the magnitude of the person's weight? W= mg = 10ox 9.8 = 980 N (d) What is the magnitude of the total force acting up on the beam? Tension forter , normal force y (e) What is the magnitude of the total force acting down on the beam? Gravity , normal Force X (f) What is the magnitude of the weight of the beam? = 10 38 N 7 X (g) What is the mass of the beam? "W= mg => 10 38 N = mx 9.8 => 105. 91 kq In ) What is the acceleration , a , of the beam ? F = ma X 1038 = 105-91 x9 = 9.8 m/s 2 is the ron and evan