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Part 1: Resultant and Equilibrant of Two Forces Table 1A Graphical Method Solution (Scale: e.g., 5 g = 1 cm; Al = 1 mm, Aangle = 10) Force Mass (g) Length (cm) Force (N) Direction () F1 25.0+0.5 5.0+0.1 0.245+0.007 20+1 F 2 35.0+0.5 7.0+0.1 0.343+0.008 70+1 Resultant (FR) 53.0+0.5 10.610.1 0.519+0.010 50+1 Equilibrant (FE) 53.0+0.5 10.6+0.1 0.519+0.010 230+1 Al and Aangle represent the absolute errors for length and direction, respectively. Table 1B Experimental Method Solution (Aangle = 10) Force Mass (g) Force (N) Direction () F1 25.0+0.5 0.245+0.007 20+1 F 2 35.0+0.5 0.343+0.008 70+1 Resultant (FR) 54.5+0.5 0.534+0.010 50+1 Equilibrant (FE) 54.5+0.5 0.534+0.010 230+1 Table 1C Analytical Method Solution Force Mass (g) Force (N) X-Comp Y-Comp (N) Direction () (N) F1 25.0+0.5 0.24 0.23 0.084 20+1 F 2 35.0+0.5 0.34 0.12 0.32 70+1 Resultant (FR) 43.0+0.5 0.42 0.26 0.33 52+1 Equilibrant (FE) 43 0.42 0.26 -0.33 232 *Suggested values to perform the experiment. You might choose your own values