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Show language L = {a^i b^j c^k | i, j, k Element Z^+, k = min (i, j)} is not a context-free language. Use the

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Show language L = {a^i b^j c^k | i, j, k Element Z^+, k = min (i, j)} is not a context-free language. Use the pumping lemma for context-free languages

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