Question
show that 1 1 eR2 S R -(x+y) dA 1 for D = {(x, y) = R | x + y < R}. For
show that 1 1 eR2 S R -(x+y) dA 1 for D = {(x, y) = R | x + y < R}. For this week, use a polar coordinate change to compute the integral exactly. e-(x+y) dA [Note: To check your answer, you can see if the inequalities from last week are satisfied.]
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