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Show that a solution of the differential equation subject to the boundary conditions ?(a) = k0 and?(b) = k1, where k0 and k1 are constant
Show that a solution of the differential equation subject to the boundary conditions ?(a) = k0 and?(b) = k1, where k0 and k1 are constant potentials, is given by ?(r) = A loge r + B, where
ko - k1 Ko loge b + k1 log, a A log (a/b) y B= log, (a/b)Step by Step Solution
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