Show that if the Lyapunov number of the orbit of x0 under the map f is L, then the Lyapunov number of the orbit of x0 under the map fk is L^k, whether or not x0 is periodic. Note that if the orbit of x0 under f is {x0, x1, x2, ...} then the orbit under fk is {x0,xk,x2k,x3k,...}. Hint: Use the chain rule.