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142 1. A pilot's true heading is 125 with a true airspeed of 110 knots.36 The wind is 20 knots at 40. If the
142 1. A pilot's true heading is 125 with a true airspeed of 110 knots.36 The wind is 20 knots at 40. If the pilot heads directly at 125 the plane will be blown off course. We wish to find the heading the pilot will use as well as the plane's groundspeed. Study Figure 2 below. AC is the true heading, BC is the wind, and AB is the heading the pilot must use to compensate for the wind. N A Figure 2 110 >B 20 Projects for Precalculus Show that mLBCA = 95. (b) Find m/CAB to the nearest tenth of a degree. This is your wind correction angle. [Note: The Law of Sines may be helpful in this question.] (c) What heading should the pilot use? (d) Find the groundspeed of the plane. [Note: The groundspeed is the length of AC.] 2. A plane is preparing to go from Holland, Michigan to Sheboygan, Wisconsin. This requires a true heading of 313. The plane is capable of a true airspeed of 125 knots. The winds aloft forecast reports that the winds are 25 knots at 50. (a) What is the wind correction angle? (b) To what heading should the pilot direct the plane? (c) What is the actual groundspeed? 3. Let's further explore the relationship between the angle of the wind and your groun speed. (a) Suppose you wish to go due north with a true airspeed of 125 knots. You have a wind at 25 knots coming from due east. Will the wind cause you to go faster, slower, or have no effect on your groundspeed? Explain. 36 A knot is a measure of speed One knot in omual hour 115 mil..
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a Show that m BCA 95 We can use the law of sines to solve for BCA ACsinBCA ABsinBAC AC 110 AB 20 BAC 40 110sinBCA 20sin40 sinBCA 20110sin40 BCA 95 b F...Get Instant Access to Expert-Tailored Solutions
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