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Show that the equation x - 11x + 1 =0 has three solutions in the interval [ - 4, 4]. Let f(x) be equal to
Show that the equation x" - 11x + 1 =0 has three solutions in the interval [ - 4, 4]. Let f(x) be equal to the left side of the equation. Where do the solutions to the equation exist? O A. Solutions exist at values of x, and x, if 0 s f(x, )
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